(x^2+3)^2+21=10x^2+30

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Solution for (x^2+3)^2+21=10x^2+30 equation: 



(x^2+3)^2+21=10x^2+30

We move all terms to the left:

(x^2+3)^2+21-(10x^2+30)=0

We get rid of parentheses

-10x^2+(x^2+3)^2-30+21=0

We add all the numbers together, and all the variables

-10x^2+(x^2+3)^2-9=0

We move all terms containing x to the left, all other terms to the right

-10x^2+(x^2+3)^2=9

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